What is the derivative of 1-2x^3 ?

The derivative of 1-2x^3 is -6x^2

What is the first derivative of 1-2x^3 ?

The first derivative of 1-2x^3 is -6x^2

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\frac{d}{d x} (1 - 2 x^{3})

- 6 x^{2}

Solution steps

\frac{d}{d x} (1 - 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 0 - 6 x^{2}

Simplify

= - 6 x^{2}

\int e^{x} sin (n x) d x

y^{^{''}} + 5 y^{^{'}} + 6 y = 12

f (x) = 2 x^{3} - 5 x^{2} + 6

\int_{- 1}^{1} x^{2} - 2 - e^{x} d x

\int_{0}^{π} sin (t) d t

What is the derivative of 1-2x^3 ?
The derivative of 1-2x^3 is -6x^2
What is the first derivative of 1-2x^3 ?
The first derivative of 1-2x^3 is -6x^2