What is the integral from 0 to pi of sin(t) ?

The integral from 0 to pi of sin(t) is 2

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integral from 0 to pi of sin(t)

\int_{0}^{π} sin (t) d t

2

Solution steps

\int_{0}^{π} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= [- cos (t)]_{0}^{π}

Compute the boundaries:

2

= 2

y^{^{'}} = 2 x - y

\frac{d}{d x} (3^{x^{2} - x + 5})

\frac{d}{d x} (\frac{x ^{2} + 10 x}{( x + 5 ) ^{2}})

\frac{\partial}{\partial x} (4 u (x, y))

\frac{1}{3 x ^{2}}

What is the integral from 0 to pi of sin(t) ?
The integral from 0 to pi of sin(t) is 2