What is the solution for x^2((dy)/(dx))=y-yx ?

The solution for x^2((dy)/(dx))=y-yx is y=(e^{(-1+c_{1}x)/x})/(x)

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x^2((dy)/(dx))=y-yx

x^{2} (\frac{d y}{d x}) = y - y x

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

Solution steps

x^{2} (\frac{d y}{d x}) = y - y x

Solve separable ODE:

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

y = x^{2} - 6 x, (5, - 5)

y^{^{''}} - 2 y^{^{'}} + 10 y = 9 e t csc (3 t)

y = ln (x x^{2} - 9)

n = 1 \sum \infty ln (\frac{n}{2 n + 1})

x \to 12 lim (25 - x^{2})

What is the solution for x^2((dy)/(dx))=y-yx ?
The solution for x^2((dy)/(dx))=y-yx is y=(e^{(-1+c_{1}x)/x})/(x)