What is the sum from n=1 to infinity of ln(n/(2n+1)) ?

The sum from n=1 to infinity of ln(n/(2n+1)) is diverges

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sum from n=1 to infinity of ln(n/(2n+1))

n = 1 \sum \infty ln (\frac{n}{2 n + 1})

diverges

Solution steps

n = 1 \sum \infty ln (\frac{n}{2 n + 1})

Apply Series Divergence Test:

diverges

= diverges

x \to 12 lim (25 - x^{2})

y = (x + 2)^{2} - 3

\int (3 x^{2} + ln (x)) d x

5 x + 4

\int \frac{sin ( 2 x )}{2 + cos ( x )} d x

What is the sum from n=1 to infinity of ln(n/(2n+1)) ?
The sum from n=1 to infinity of ln(n/(2n+1)) is diverges