What is the derivative of x^4-4x ?

The derivative of x^4-4x is 4x^3-4

What is the first derivative of x^4-4x ?

The first derivative of x^4-4x is 4x^3-4

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\frac{d}{d x} (x^{4} - 4 x)

4 x^{3} - 4

Solution steps

\frac{d}{d x} (x^{4} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x) = 4

= 4 x^{3} - 4

\frac{\partial}{\partial x} (x^{2} sin (y))

\frac{d}{d x} ((5 x + 7)^{2})

\int_{0}^{0.3} 600 x d x

f (x) = 2 ln (x)

What is the derivative of x^4-4x ?
The derivative of x^4-4x is 4x^3-4
What is the first derivative of x^4-4x ?
The first derivative of x^4-4x is 4x^3-4