What is the integral of 1/2 \sqrt[3]{x} ?

The integral of 1/2 \sqrt[3]{x} is 3/8 x^{4/3}+C

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integral of 1/2 \sqrt[3]{x}

\frac{3}{8} x^{\frac{4}{3}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= \frac{1}{2} \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

\frac{1}{2} \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{3}{8} x^{\frac{4}{3}}

= \frac{3}{8} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{8} x^{\frac{4}{3}} + C

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\frac{\partial}{\partial y} (cos (8 x) sin (2 y))

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n = 0 \sum \infty \frac{1}{n ^{3} + 1}

7 x^{\frac{1}{5}} (x^{3} - 2)

What is the integral of 1/2 \sqrt[3]{x} ?
The integral of 1/2 \sqrt[3]{x} is 3/8 x^{4/3}+C