What is the limit as x approaches 0+of arcsin(2x-1) ?

The limit as x approaches 0+of arcsin(2x-1) is -pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of arcsin(2x-1)

x \to 0 + lim (arcsin (2 x - 1))

- \frac{π}{2}

Decimal Notation

- 1.57079 \dots

Solution steps

x \to 0 + lim (arcsin (2 x - 1))

Plug in the value

x = 0

= arcsin (2 \cdot 0 - 1)

Simplify

arcsin (2 \cdot 0 - 1) : - \frac{π}{2}

= - \frac{π}{2}

\frac{d y}{d x}, 3 x^{3} y = 6

x \to π lim (cos (\frac{x}{6}))

f (x) = - \frac{1}{4} x^{4} + \frac{27}{2} x^{2}

\int \frac{m ^{2}}{m + 1} d m

\frac{64 x}{x ^{2} + 64}

What is the limit as x approaches 0+of arcsin(2x-1) ?
The limit as x approaches 0+of arcsin(2x-1) is -pi/2