What is the derivative of (64x)/(x^2+64) ?

The derivative of (64x)/(x^2+64) is (64(-x^2+64))/((x^2+64)^2)

What is the first derivative of (64x)/(x^2+64) ?

The first derivative of (64x)/(x^2+64) is (64(-x^2+64))/((x^2+64)^2)

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derivative of

\frac{64 x}{x ^{2} + 64}

\frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{64 x}{x ^{2} + 64})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (\frac{x}{x ^{2} + 64})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 64 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 64 ) - \frac{d}{d x} ( x ^{2} + 64 ) x}{( x ^{2} + 64 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 64) = 2 x

= 64 \cdot \frac{1 \cdot ( x ^{2} + 64 ) - 2 xx}{( x ^{2} + 64 ) ^{2}}

Simplify

64 \cdot \frac{1 \cdot ( x ^{2} + 64 ) - 2 xx}{( x ^{2} + 64 ) ^{2}} : \frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

= \frac{64 ( - x ^{2} + 64 )}{( x ^{2} + 64 ) ^{2}}

\int x^{2} ln (x) d x

\frac{d}{d x} (x^{4} - 5 x^{3})

\frac{d}{d x} (\frac{x + 10}{x - 10})

\int x 1 + x d x

ln (8 x + 5)

What is the derivative of (64x)/(x^2+64) ?
The derivative of (64x)/(x^2+64) is (64(-x^2+64))/((x^2+64)^2)
What is the first derivative of (64x)/(x^2+64) ?
The first derivative of (64x)/(x^2+64) is (64(-x^2+64))/((x^2+64)^2)