What is the integral of xsqrt(1+x) ?

The integral of xsqrt(1+x) is 2/5 (1+x)^{5/2}-2/3 (1+x)^{3/2}+C

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integral of xsqrt(1+x)

\int x 1 + x d x

\frac{2}{5} (1 + x)^{\frac{5}{2}} - \frac{2}{3} (1 + x)^{\frac{3}{2}} + C

Solution steps

\int x 1 + x d x

Apply u-substitution

: \int (u - 1) u d u

= \int (u - 1) u d u

Expand

(u - 1) u : u^{\frac{3}{2}} - u

= \int u^{\frac{3}{2}} - u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u - \int u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} - \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 1 + x

= \frac{2}{5} (1 + x)^{\frac{5}{2}} - \frac{2}{3} (1 + x)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (1 + x)^{\frac{5}{2}} - \frac{2}{3} (1 + x)^{\frac{3}{2}} + C

ln (8 x + 5)

x y^{^{'}} + 9 y = 12 y^{2}, y (1) = - 1

\frac{d}{d x} (x \cdot a)

\int \frac{1}{( x ^{2} + 1 ) ^{4}} d x

\int \frac{2 x + 1}{x ^{2} - x} d x

What is the integral of xsqrt(1+x) ?
The integral of xsqrt(1+x) is 2/5 (1+x)^{5/2}-2/3 (1+x)^{3/2}+C