What is the derivative of arcsec^2(x) ?

The derivative of arcsec^2(x) is (2arcsec(x))/(xsqrt(x^2-1))

What is the first derivative of arcsec^2(x) ?

The first derivative of arcsec^2(x) is (2arcsec(x))/(xsqrt(x^2-1))

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\frac{d}{d x} (arcsec^{2} (x))

\frac{2 arcsec ( x )}{x x ^{2} - 1}

Solution steps

\frac{d}{d x} (arcsec^{2} (x))

Apply the chain rule:

2 arcsec (x) \frac{d}{d x} (arcsec (x))

= 2 arcsec (x) \frac{d}{d x} (arcsec (x))

\frac{d}{d x} (arcsec (x)) = \frac{1}{x ^{2} x ^{2} - 1}

= 2 arcsec (x) \frac{1}{x ^{2} x ^{2} - 1}

Simplify

2 arcsec (x) \frac{1}{x ^{2} x ^{2} - 1} : \frac{2 arcsec ( x )}{x x ^{2} - 1}

= \frac{2 arcsec ( x )}{x x ^{2} - 1}

x \to 0 lim (\frac{5}{tan ( 3 x )})

8 \frac{d y}{d x} + 7 e^{x + y} = 0

y^{^{'}} = t y

z \to 0 lim (\frac{1}{1 + z ^{2}})

\frac{d}{d x} (\frac{ln ( x ^{2} )}{x})

What is the derivative of arcsec^2(x) ?
The derivative of arcsec^2(x) is (2arcsec(x))/(xsqrt(x^2-1))
What is the first derivative of arcsec^2(x) ?
The first derivative of arcsec^2(x) is (2arcsec(x))/(xsqrt(x^2-1))