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Popular >

xy^'+y=6xy^2

Solution

x y^{^{'}} + y = 6 x y^{2}

Solution

y = \frac{1}{x ( - 6 ln ( x ) + c _{1} )}

Solution steps

x y^{'} (x) + y = 6 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 6 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 6 ln ( x ) + c _{1} )}

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=6xy^2 ?
The solution for xy^'+y=6xy^2 is y= 1/(x(-6ln(x)+c_{1))}