What is the integral from 0 to 2 of xsqrt(x^2+2) ?

The integral from 0 to 2 of xsqrt(x^2+2) is 2sqrt(6)-(2sqrt(2))/3

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integral from 0 to 2 of xsqrt(x^2+2)

\int_{0}^{2} x x^{2} + 2 d x

26 - \frac{2 2}{3}

Decimal Notation

3.95617 \dots

Solution steps

\int_{0}^{2} x x^{2} + 2 d x

Apply u-substitution

: \int_{2}^{6} u^{2} d u

= \int_{2}^{6} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{2}^{6}

= [\frac{u ^{3}}{3}]_{2}^{6}

Compute the boundaries:

26 - \frac{2 2}{3}

= 26 - \frac{2 2}{3}

\int_{0}^{4} (2 x + 5) d x

x^{2} f (x)

\int \frac{1}{- \frac{1}{x ^{2}} + 2 x} - 3 d x

\frac{1}{( s ^{2} + 4 ) ^{2} \cdot s}

f (x) = x^{3} ln (2 x), at x = 5

What is the integral from 0 to 2 of xsqrt(x^2+2) ?
The integral from 0 to 2 of xsqrt(x^2+2) is 2sqrt(6)-(2sqrt(2))/3