en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x(x+1)^2,y=0

Solution

area

y = x (x + 1)^{2}, y = 0

Solution

\frac{1}{12}

+1

Decimal Notation

0.08333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{0} ∣ x ∣ ∣ x + 1 ∣^{2} d x

Solve

\int_{- 1}^{0} ∣ x ∣ ∣ x + 1 ∣^{2} d x : \frac{1}{12}

The area is:

= \frac{1}{12}

Popular Examples

integral from 0 to pi/(12) of cos(4x)

\int_{0}^{\frac{π}{12}} cos (4 x) d x

derivative of f(x)=sqrt(sin^3(18x))derivative of

f (x) = sin^{3} (18 x)

limit as x approaches 3 of x^2-7

x \to 3 lim (x^{2} - 7)

limit as x approaches+0+of 0/x

x \to + 0 + lim (\frac{0}{x})

limit as x approaches 3 of cos(x)

x \to 3 lim (cos (x))

Frequently Asked Questions (FAQ)

What is area y=x(x+1)^2,y=0 ?
The answer to area y=x(x+1)^2,y=0 is 1/12