What is the derivative of e^{2^x} ?

The derivative of e^{2^x} is e^{2^x}*2^xln(2)

What is the first derivative of e^{2^x} ?

The first derivative of e^{2^x} is e^{2^x}*2^xln(2)

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\frac{d}{d x} (e^{2^{x}})

e^{2^{x}} \cdot 2^{x} ln (2)

Solution steps

\frac{d}{d x} (e^{2^{x}})

Apply the chain rule:

e^{2^{x}} \frac{d}{d x} (2^{x})

= e^{2^{x}} \frac{d}{d x} (2^{x})

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

= e^{2^{x}} \cdot 2^{x} ln (2)

d x + e^{- 5 x} d y = 0

f (x) = 2 ln (6 + x)

\frac{d}{d x} (\frac{3}{lo g _{8} ( x )})

x \cdot y^{^{'}} - y = \frac{5}{4} \cdot x \cdot ln (x)

\int \frac{x}{1 + 2 x ^{2}} d x

What is the derivative of e^{2^x} ?
The derivative of e^{2^x} is e^{2^x}*2^xln(2)
What is the first derivative of e^{2^x} ?
The first derivative of e^{2^x} is e^{2^x}*2^xln(2)