What is the derivative of-4/((2x+1^2)) ?

The derivative of-4/((2x+1^2)) is (16)/((2x+1)^3)

What is the first derivative of-4/((2x+1^2)) ?

The first derivative of-4/((2x+1^2)) is (16)/((2x+1)^3)

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\frac{d}{d x} (- \frac{4}{( 2 x + 1 ) ^{2}})

\frac{16}{( 2 x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{4}{( 2 x + 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{1}{( 2 x + 1 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 4 \frac{d}{d x} ((2 x + 1)^{- 2})

Apply the chain rule:

- \frac{2}{( 2 x + 1 ) ^{3}} \frac{d}{d x} (2 x + 1)

= - \frac{2}{( 2 x + 1 ) ^{3}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= - 4 (- \frac{2}{( 2 x + 1 ) ^{3}} \cdot 2)

Simplify

- 4 (- \frac{2}{( 2 x + 1 ) ^{3}} \cdot 2) : \frac{16}{( 2 x + 1 ) ^{3}}

= \frac{16}{( 2 x + 1 ) ^{3}}

e^{s^{2}}

\int x^{3} (x^{4} + 2)^{5} d x

y = x^{5} 3^{x}

- \frac{1}{x ^{2}} + sec^{2} (x)

x \to 1 + lim (\frac{3 x}{x ^{2} - 1})

What is the derivative of-4/((2x+1^2)) ?
The derivative of-4/((2x+1^2)) is (16)/((2x+1)^3)
What is the first derivative of-4/((2x+1^2)) ?
The first derivative of-4/((2x+1^2)) is (16)/((2x+1)^3)