What is the derivative of f(x)=cos^2(3x+1) ?

The derivative of f(x)=cos^2(3x+1) is -6cos(3x+1)sin(3x+1)

What is the first derivative of f(x)=cos^2(3x+1) ?

The first derivative of f(x)=cos^2(3x+1) is -6cos(3x+1)sin(3x+1)

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derivative of

f (x) = cos^{2} (3 x + 1)

- 6 cos (3 x + 1) sin (3 x + 1)

Solution steps

\frac{d}{d x} (cos^{2} (3 x + 1))

Apply the chain rule:

2 cos (3 x + 1) \frac{d}{d x} (cos (3 x + 1))

= 2 cos (3 x + 1) \frac{d}{d x} (cos (3 x + 1))

\frac{d}{d x} (cos (3 x + 1)) = - sin (3 x + 1) \cdot 3

= 2 cos (3 x + 1) (- sin (3 x + 1) \cdot 3)

Simplify

= - 6 cos (3 x + 1) sin (3 x + 1)

\frac{d}{d x} (ln (4 + x^{2}))

y^{^{'}} - 5 y = 9 e^{8 t}

\int \frac{2}{2 x + 3} d x

y^{^{''}} + 4 y^{^{'}} + 5 y = 35 e^{- 4 x}, y (0) = - 3, y^{^{'}} (0) = 1

4 x^{^{'}} + x = 5

What is the derivative of f(x)=cos^2(3x+1) ?
The derivative of f(x)=cos^2(3x+1) is -6cos(3x+1)sin(3x+1)
What is the first derivative of f(x)=cos^2(3x+1) ?
The first derivative of f(x)=cos^2(3x+1) is -6cos(3x+1)sin(3x+1)