What is the derivative of f(x)=sin(9ln(x)) ?

The derivative of f(x)=sin(9ln(x)) is (9cos(9ln(x)))/x

What is the first derivative of f(x)=sin(9ln(x)) ?

The first derivative of f(x)=sin(9ln(x)) is (9cos(9ln(x)))/x

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derivative of

f (x) = sin (9 ln (x))

\frac{9 cos ( 9 ln ( x ) )}{x}

Solution steps

\frac{d}{d x} (sin (9 ln (x)))

Apply the chain rule:

cos (9 ln (x)) \frac{d}{d x} (9 ln (x))

= cos (9 ln (x)) \frac{d}{d x} (9 ln (x))

\frac{d}{d x} (9 ln (x)) = \frac{9}{x}

= cos (9 ln (x)) \frac{9}{x}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{9 cos ( 9 ln ( x ) )}{x}

y^{^{''}} + 4 y = sin (x), y (0) = 1, y^{^{'}} (0) = 4

\int 4 e^{x^{2}} d x

\int_{0}^{\frac{π}{4}} 2 sec^{2} (x) d x

\int \frac{x + 3}{2 x ^{3} - 8 x} d x

y = 2 x tan (x), at x = π

What is the derivative of f(x)=sin(9ln(x)) ?
The derivative of f(x)=sin(9ln(x)) is (9cos(9ln(x)))/x
What is the first derivative of f(x)=sin(9ln(x)) ?
The first derivative of f(x)=sin(9ln(x)) is (9cos(9ln(x)))/x