What is the tangent of y=2xtan(x),\at x=pi ?

The tangent of y=2xtan(x),\at x=pi is y=2pix-2pi^2

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tangent of y=2xtan(x),\at x=pi

tangent of

y = 2 x tan (x), at x = π

y = 2 π x - 2 π^{2}

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

y = 2 x tan (x) : \frac{d y}{d x} = 2 (tan (x) + x sec^{2} (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 π

Find the line with slope m=

2 π

and passing through

(π, 0) : y = 2 π x - 2 π^{2}

y = 2 π x - 2 π^{2}

x \to 0 lim (\frac{2 x - 1}{x})

\int \frac{sin ( 2 x )}{2 cos ^{2} ( x )} d x

\frac{d}{d x} (- 32 sin (2 x))

1 + x - x^{2} - x^{3}, 1 - x, [- 2, 1]

\frac{\partial}{\partial y} (cos (yz))

What is the tangent of y=2xtan(x),\at x=pi ?
The tangent of y=2xtan(x),\at x=pi is y=2pix-2pi^2