What is the derivative of-32sin(2x) ?

The derivative of-32sin(2x) is -64cos(2x)

What is the first derivative of-32sin(2x) ?

The first derivative of-32sin(2x) is -64cos(2x)

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\frac{d}{d x} (- 32 sin (2 x))

- 64 cos (2 x)

Solution steps

\frac{d}{d x} (- 32 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 32 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 32 cos (2 x) \cdot 2

Simplify

= - 64 cos (2 x)

1 + x - x^{2} - x^{3}, 1 - x, [- 2, 1]

\frac{\partial}{\partial y} (cos (yz))

(x + 2) sin (y) + (x cos (y)) y^{^{'}} = 0

x \to 0 + lim (ln (0) - \frac{1}{x})

\int_{- 1}^{3} \frac{1}{x ^{2}} d x

What is the derivative of-32sin(2x) ?
The derivative of-32sin(2x) is -64cos(2x)
What is the first derivative of-32sin(2x) ?
The first derivative of-32sin(2x) is -64cos(2x)