What is the derivative of 8x+sqrt(x) ?

The derivative of 8x+sqrt(x) is 8+1/(2sqrt(x))

What is the first derivative of 8x+sqrt(x) ?

The first derivative of 8x+sqrt(x) is 8+1/(2sqrt(x))

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derivative of

8 x + x

8 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (8 x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (x)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (x) = \frac{1}{2 x}

= 8 + \frac{1}{2 x}

\int \frac{x ^{6} - x}{x ^{3}} d x

\int \frac{x + 2}{x ^{2} + 7 x - 8} d x

2.87 y^{^{''}} + 10.5 y^{^{'}} - 1.83 y = 0

y^{^{'}} = y^{2} (1 + e^{x})

\frac{d}{d x} (\frac{4 x ^{5} + 7}{x ^{3}})

What is the derivative of 8x+sqrt(x) ?
The derivative of 8x+sqrt(x) is 8+1/(2sqrt(x))
What is the first derivative of 8x+sqrt(x) ?
The first derivative of 8x+sqrt(x) is 8+1/(2sqrt(x))