What is (\partial)/(\partial x)(3xy^2+16x^2y^3) ?

The answer to (\partial)/(\partial x)(3xy^2+16x^2y^3) is 3y^2+32y^3x

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(\partial)/(\partial x)(3xy^2+16x^2y^3)

\frac{\partial}{\partial x} (3 x y^{2} + 16 x^{2} y^{3})

3 y^{2} + 32 y^{3} x

Solution steps

\frac{\partial}{\partial x} (3 x y^{2} + 16 x^{2} y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x y^{2}) + \frac{\partial}{\partial x} (16 x^{2} y^{3})

\frac{\partial}{\partial x} (3 x y^{2}) = 3 y^{2}

\frac{\partial}{\partial x} (16 x^{2} y^{3}) = 32 y^{3} x

= 3 y^{2} + 32 y^{3} x

\int θ tan (8) θ^{2} d θ

\frac{\partial}{\partial x} (e^{x y} ln (9 y))

\frac{d}{d x} (5 - \frac{2}{x})

\int_{3}^{\infty} \frac{ln ( x )}{x} d x

x \to 0 - lim (\frac{∣ x ∣}{x})

What is (\partial)/(\partial x)(3xy^2+16x^2y^3) ?
The answer to (\partial)/(\partial x)(3xy^2+16x^2y^3) is 3y^2+32y^3x