What is the integral of sin^3(6x)cos(6x) ?

The integral of sin^3(6x)cos(6x) is 1/24 sin^4(6x)+C

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integral of sin^3(6x)cos(6x)

\int sin^{3} (6 x) cos (6 x) d x

\frac{1}{24} sin^{4} (6 x) + C

Solution steps

\int sin^{3} (6 x) cos (6 x) d x

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{3}{4} u^{\frac{4}{3}}

= \frac{1}{18} \cdot \frac{3}{4} u^{\frac{4}{3}}

Substitute back

u = sin^{3} (6 x)

= \frac{1}{18} \cdot \frac{3}{4} (sin^{3} (6 x))^{\frac{4}{3}}

Simplify

\frac{1}{18} \cdot \frac{3}{4} (sin^{3} (6 x))^{\frac{4}{3}} : \frac{1}{24} sin^{4} (6 x)

= \frac{1}{24} sin^{4} (6 x)

Add a constant to the solution

= \frac{1}{24} sin^{4} (6 x) + C

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What is the integral of sin^3(6x)cos(6x) ?
The integral of sin^3(6x)cos(6x) is 1/24 sin^4(6x)+C