What is the integral of x3^{-x^2} ?

The integral of x3^{-x^2} is -1/(2ln(3))*3^{-x^2}+C

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integral of x3^{-x^2}

\int x 3^{- x^{2}} d x

- \frac{1}{2 ln ( 3 )} \cdot 3^{- x^{2}} + C

Solution steps

\int x \cdot 3^{- x^{2}} d x

Apply u-substitution

: \int - \frac{1}{2 ln ( 3 )} d u

= \int - \frac{1}{2 ln ( 3 )} d u

Integral of a constant:

\int a d x = a x

= (- \frac{1}{2 ln ( 3 )}) u

Substitute back

u = 3^{- x^{2}}

= (- \frac{1}{2 ln ( 3 )}) \cdot 3^{- x^{2}}

Simplify

= - \frac{1}{2 ln ( 3 )} \cdot 3^{- x^{2}}

Add a constant to the solution

= - \frac{1}{2 ln ( 3 )} \cdot 3^{- x^{2}} + C

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What is the integral of x3^{-x^2} ?
The integral of x3^{-x^2} is -1/(2ln(3))*3^{-x^2}+C