What is the integral of 1/x+1/(x^3) ?

The integral of 1/x+1/(x^3) is ln|x|-1/(2x^2)+C

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integral of 1/x+1/(x^3)

\int \frac{1}{x} + \frac{1}{x ^{3}} d x

ln ∣ x ∣ - \frac{1}{2 x ^{2}} + C

Solution steps

\int \frac{1}{x} + \frac{1}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int \frac{1}{x ^{3}} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}}

= ln ∣ x ∣ - \frac{1}{2 x ^{2}}

Add a constant to the solution

= ln ∣ x ∣ - \frac{1}{2 x ^{2}} + C

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What is the integral of 1/x+1/(x^3) ?
The integral of 1/x+1/(x^3) is ln|x|-1/(2x^2)+C