What is the integral of cos(x)+1/7 x ?

The integral of cos(x)+1/7 x is sin(x)+(x^2)/(14)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(x)+1/7 x

\int cos (x) + \frac{1}{7} x d x

sin (x) + \frac{x ^{2}}{14} + C

Solution steps

\int cos (x) + \frac{1}{7} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x + \int \frac{1}{7} x d x

\int cos (x) d x = sin (x)

\int \frac{1}{7} x d x = \frac{x ^{2}}{14}

= sin (x) + \frac{x ^{2}}{14}

Add a constant to the solution

= sin (x) + \frac{x ^{2}}{14} + C

\int (e^{a x} + e^{- a x})^{2} d x

\int x^{3} (1 - 5 x^{2})^{10} d x

\int \frac{x ^{4}}{x ^{4} - 216 x} d x

\int \frac{x ^{2}}{( x ^{2} - 1 ) ^{5}} d x

\int - 2 z e^{- 2 yz} d y

What is the integral of cos(x)+1/7 x ?
The integral of cos(x)+1/7 x is sin(x)+(x^2)/(14)+C