What is the integral of (e^{x+1})/(1+e^x) ?

The integral of (e^{x+1})/(1+e^x) is eln|1+e^x|+C

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integral of (e^{x+1})/(1+e^x)

\int \frac{e ^{x + 1}}{1 + e ^{x}} d x

e ln ∣ 1 + e^{x} ∣ + C

Solution steps

\int \frac{e ^{x + 1}}{1 + e ^{x}} d x

Apply u-substitution

: \int \frac{e}{u} d u

= \int \frac{e}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= e ln ∣ u ∣

Substitute back

u = 1 + e^{x}

= e ln ∣ 1 + e^{x} ∣

Add a constant to the solution

= e ln ∣ 1 + e^{x} ∣ + C

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What is the integral of (e^{x+1})/(1+e^x) ?
The integral of (e^{x+1})/(1+e^x) is eln|1+e^x|+C