What is the integral of 6x^2+2x+4 ?

The integral of 6x^2+2x+4 is 2x^3+x^2+4x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6x^2+2x+4

\int 6 x^{2} + 2 x + 4 d x

2 x^{3} + x^{2} + 4 x + C

Solution steps

\int 6 x^{2} + 2 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{2} d x + \int 2 x d x + \int 4 d x

\int 6 x^{2} d x = 2 x^{3}

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= 2 x^{3} + x^{2} + 4 x

Add a constant to the solution

= 2 x^{3} + x^{2} + 4 x + C

\int x^{3} + \frac{2}{5 - 6 x} + 3 cos (5 - 7 x) d x

\int 7 x e^{3 x^{2}} d x

\int e^{2 x} 4 x d x

\int - x^{2} - 2 x + 3 d x

\int (x + 17) 34 x + x^{2} d x