What is the integral of (x^3+4x^2-x+5)cos(3x) ?

The integral of (x^3+4x^2-x+5)cos(3x) is

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integral of (x^3+4x^2-x+5)cos(3x)

\int (x^{3} + 4 x^{2} - x + 5) cos (3 x) d x

\frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) + \frac{4}{3} x^{2} sin (3 x) - \frac{5}{9} x sin (3 x) + \frac{8}{9} x cos (3 x) - \frac{5}{27} cos (3 x) + \frac{37}{27} sin (3 x) + C

Solution steps

\int (x^{3} + 4 x^{2} - x + 5) cos (3 x) d x

Expand

(x^{3} + 4 x^{2} - x + 5) cos (3 x) : x^{3} cos (3 x) + 4 x^{2} cos (3 x) - x cos (3 x) + 5 cos (3 x)

= \int x^{3} cos (3 x) + 4 x^{2} cos (3 x) - x cos (3 x) + 5 cos (3 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} cos (3 x) d x + \int 4 x^{2} cos (3 x) d x - \int x cos (3 x) d x + \int 5 cos (3 x) d x

\int x^{3} cos (3 x) d x = \frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) - \frac{2}{9} x sin (3 x) - \frac{2}{27} cos (3 x)

\int 4 x^{2} cos (3 x) d x = \frac{4}{27} (9 x^{2} sin (3 x) - 2 (- 3 x cos (3 x) + sin (3 x)))

\int x cos (3 x) d x = \frac{1}{9} (3 x sin (3 x) + cos (3 x))

\int 5 cos (3 x) d x = \frac{5}{3} sin (3 x)

= \frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) - \frac{2}{9} x sin (3 x) - \frac{2}{27} cos (3 x) + \frac{4}{27} (9 x^{2} sin (3 x) - 2 (- 3 x cos (3 x) + sin (3 x))) - \frac{1}{9} (3 x sin (3 x) + cos (3 x)) + \frac{5}{3} sin (3 x)

Simplify

\frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) - \frac{2}{9} x sin (3 x) - \frac{2}{27} cos (3 x) + \frac{4}{27} (9 x^{2} sin (3 x) - 2 (- 3 x cos (3 x) + sin (3 x))) - \frac{1}{9} (3 x sin (3 x) + cos (3 x)) + \frac{5}{3} sin (3 x) : \frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) + \frac{4}{3} x^{2} sin (3 x) - \frac{5}{9} x sin (3 x) + \frac{8}{9} x cos (3 x) - \frac{5}{27} cos (3 x) + \frac{37}{27} sin (3 x)

= \frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) + \frac{4}{3} x^{2} sin (3 x) - \frac{5}{9} x sin (3 x) + \frac{8}{9} x cos (3 x) - \frac{5}{27} cos (3 x) + \frac{37}{27} sin (3 x)

Add a constant to the solution

= \frac{1}{3} x^{3} sin (3 x) + \frac{1}{3} x^{2} cos (3 x) + \frac{4}{3} x^{2} sin (3 x) - \frac{5}{9} x sin (3 x) + \frac{8}{9} x cos (3 x) - \frac{5}{27} cos (3 x) + \frac{37}{27} sin (3 x) + C

\int x \cdot arccos (x) d x

\int \frac{4}{( x - 3 ) ^{5}} d x

\int x sin (x) x d x

\int z^{7} d z

\int (1 + 30 x) x d x

What is the integral of (x^3+4x^2-x+5)cos(3x) ?
The integral of (x^3+4x^2-x+5)cos(3x) is