What is the integral of sin(x)In(cos(x)) ?

The integral of sin(x)In(cos(x)) is (In)/2 sin^2(x)+C

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integral of sin(x)In(cos(x))

\int sin (x) I n (cos (x)) d x

\frac{I n}{2} sin^{2} (x) + C

Solution steps

\int sin (x) I n cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= I n \cdot \int cos (x) sin (x) d x

Apply u-substitution

: \int u d u

= I n \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= I n \frac{u ^{2}}{2}

Substitute back

u = sin (x)

= I n \frac{sin ^{2} ( x )}{2}

Simplify

I n \frac{sin ^{2} ( x )}{2} : \frac{I n}{2} sin^{2} (x)

= \frac{I n}{2} sin^{2} (x)

Add a constant to the solution

= \frac{I n}{2} sin^{2} (x) + C

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What is the integral of sin(x)In(cos(x)) ?
The integral of sin(x)In(cos(x)) is (In)/2 sin^2(x)+C