What is the integral of 1/(xln(x)ln(x)) ?

The integral of 1/(xln(x)ln(x)) is -1/(ln(x))+C

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integral of 1/(xln(x)ln(x))

\int \frac{1}{x ln ( x ) ln ( x )} d x

- \frac{1}{ln ( x )} + C

Solution steps

\int \frac{1}{x ln ( x ) ln ( x )} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= - \frac{1}{u}

Substitute back

u = ln (x)

= - \frac{1}{ln ( x )}

Add a constant to the solution

= - \frac{1}{ln ( x )} + C

\int 2 x (x^{2} - 1)^{99} d x

\int \frac{1}{x x ^{2}} d x

\int \frac{5}{x ln ( 8 x )} d x

\int \frac{x ^{3}}{( 1 - x ) ^{2}} d x

\int (x - 4) (x^{2} - 8 x)^{3} d x

What is the integral of 1/(xln(x)ln(x)) ?
The integral of 1/(xln(x)ln(x)) is -1/(ln(x))+C