What is the integral of sqrt(x)inx ?

The integral of sqrt(x)inx is in 2/5 x^{5/2}+C

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integral of sqrt(x)inx

\int x in x d x

in \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int x in x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= in \cdot \int x x d x

Simplify

x x : x^{\frac{3}{2}}

= in \cdot \int x^{\frac{3}{2}} d x

Apply the Power Rule

: \frac{2}{5} x^{\frac{5}{2}}

= in \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= in \frac{2}{5} x^{\frac{5}{2}} + C

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What is the integral of sqrt(x)inx ?
The integral of sqrt(x)inx is in 2/5 x^{5/2}+C