What is the integral of ((x+2))/((x-3)) ?

The integral of ((x+2))/((x-3)) is 5ln|x-3|+x+C

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integral of ((x+2))/((x-3))

\int \frac{( x + 2 )}{( x - 3 )} d x

5 ln ∣ x - 3 ∣ + x + C

Solution steps

\int \frac{x + 2}{x - 3} d x

\frac{x + 2}{x - 3} = \frac{5}{x - 3} + 1

= \int \frac{5}{x - 3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{5}{x - 3} d x + \int 1 d x

\int \frac{5}{x - 3} d x = 5 ln ∣ x - 3 ∣

\int 1 d x = x

= 5 ln ∣ x - 3 ∣ + x

Add a constant to the solution

= 5 ln ∣ x - 3 ∣ + x + C

\int \frac{2}{( 2 x + 1 ) ln ( 2 x + 1 )} d x

\int (2^{x} + x^{2})^{2} d x

\int \frac{2 x - 5}{x ^{2} - 5 x + 2} d x

\int \frac{2 x ^{2}}{x - 1} d x

\int (4 - 5 x)^{- \frac{3}{2}} d x

What is the integral of ((x+2))/((x-3)) ?
The integral of ((x+2))/((x-3)) is 5ln|x-3|+x+C