What is the integral of x^{1.4}+9x^{3.5} ?

The integral of x^{1.4}+9x^{3.5} is 0.41666…x^{2.4}+2x^{4.5}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x^{1.4}+9x^{3.5}

\int x^{1.4} + 9 x^{3.5} d x

0.41666 \dots x^{2.4} + 2 x^{4.5} + C

Solution steps

\int x^{1.4} + 9 x^{3.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{1.4} d x + \int 9 x^{3.5} d x

\int x^{1.4} d x = 0.41666 \dots x^{2.4}

\int 9 x^{3.5} d x = 2 x^{4.5}

= 0.41666 \dots x^{2.4} + 2 x^{4.5}

Add a constant to the solution

= 0.41666 \dots x^{2.4} + 2 x^{4.5} + C

\int \frac{y}{( 1 + y ^{2} ) ^{2}} d y

\int - 10 x^{4} + 8 x^{3} d x

\int sec^{2} (5 x + 3) d x

\int 10 x e^{- x} d x

\int p (p + 5)^{6} d p

What is the integral of x^{1.4}+9x^{3.5} ?
The integral of x^{1.4}+9x^{3.5} is 0.41666…x^{2.4}+2x^{4.5}+C