What is the integral of e^{x-2}-e ?

The integral of e^{x-2}-e is e^{x-2}-ex+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{x-2}-e

\int e^{x - 2} - e d x

e^{x - 2} - e x + C

Solution steps

\int e^{x - 2} - e d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x - 2} d x - \int e d x

\int e^{x - 2} d x = e^{x - 2}

\int e d x = e x

= e^{x - 2} - e x

Add a constant to the solution

= e^{x - 2} - e x + C

\int \frac{x}{( 3 - x ) ^{7}} d x

\int \frac{1}{( x ^{4} + 4 )} d x

\int 3 x^{2} + 2 x - 5 d x

\int 5 cot^{5} (x) d x