What is the integral of (7sqrt(x^3)+6\sqrt[3]{x^2}) ?

The integral of (7sqrt(x^3)+6\sqrt[3]{x^2}) is 14/5 x^{5/2}+18/5 x^{5/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (7sqrt(x^3)+6\sqrt[3]{x^2})

\frac{14}{5} x^{\frac{5}{2}} + \frac{18}{5} x^{\frac{5}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 7 x^{3} d x = \frac{14}{5} x^{\frac{5}{2}}

= \frac{14}{5} x^{\frac{5}{2}} + \frac{18}{5} x^{\frac{5}{3}}

Add a constant to the solution

= \frac{14}{5} x^{\frac{5}{2}} + \frac{18}{5} x^{\frac{5}{3}} + C

\int cos (10 x + 2) cos (8 x - 2) d x

\int \frac{x ^{3} + x ^{2} - 2}{x ^{3} + x ^{2}} d x

\int \frac{1}{2 π} e^{- \frac{1}{2} x^{2}} d x

\int \frac{x}{( x ^{2} + 5 )} d x

\int \frac{1}{x ^{2} \cdot x ^{2} - 16} d x

What is the integral of (7sqrt(x^3)+6\sqrt[3]{x^2}) ?
The integral of (7sqrt(x^3)+6\sqrt[3]{x^2}) is 14/5 x^{5/2}+18/5 x^{5/3}+C