What is the integral of 1/((sin(x))) ?

The integral of 1/((sin(x))) is ln|tan(x/2)|+C

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integral of 1/((sin(x)))

\int \frac{1}{( sin ( x ) )} d x

ln tan (\frac{x}{2}) + C

Solution steps

\int \frac{1}{sin ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = tan (\frac{x}{2})

= ln tan (\frac{x}{2})

Add a constant to the solution

= ln tan (\frac{x}{2}) + C

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y

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What is the integral of 1/((sin(x))) ?
The integral of 1/((sin(x))) is ln|tan(x/2)|+C