What is the derivative of y= 1/(2cos^2(x)) ?

The derivative of y= 1/(2cos^2(x)) is sec^3(x)sin(x)

What is the first derivative of y= 1/(2cos^2(x)) ?

The first derivative of y= 1/(2cos^2(x)) is sec^3(x)sin(x)

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derivative of

y = \frac{1}{2 cos ^{2} ( x )}

sec^{3} (x) sin (x)

Solution steps

\frac{d}{d x} (\frac{1}{2 cos ^{2} ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{cos ^{2} ( x )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (cos^{- 2} (x))

Apply the chain rule:

- \frac{2}{( cos ( x ) ) ^{3}} \frac{d}{d x} (cos (x))

= - \frac{2}{( cos ( x ) ) ^{3}} \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= \frac{1}{2} (- \frac{2}{( cos ( x ) ) ^{3}} (- sin (x)))

Simplify

\frac{1}{2} (- \frac{2}{cos ^{3} ( x )} (- sin (x))) : sec^{3} (x) sin (x)

= sec^{3} (x) sin (x)

i = 0 \sum \infty \frac{i}{2 ^{i}}

\frac{d y}{d x} = \frac{x ^{3}}{y}

\int \frac{x}{( x + 1 ) ^{8}} d x

\int \frac{e ^{5 x}}{e ^{5 x} + 4} d x

\frac{\partial}{\partial y} (π x^{2} y)

What is the derivative of y= 1/(2cos^2(x)) ?
The derivative of y= 1/(2cos^2(x)) is sec^3(x)sin(x)
What is the first derivative of y= 1/(2cos^2(x)) ?
The first derivative of y= 1/(2cos^2(x)) is sec^3(x)sin(x)