What is the integral of-6x+192-168 ?

The integral of-6x+192-168 is -3x^2+24x+C

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integral of-6x+192-168

\int - 6 x + 192 - 168 d x

- 3 x^{2} + 24 x + C

Solution steps

\int - 6 x + 192 - 168 d x

Simplify

= \int - 6 x + 24 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 6 x d x + \int 24 d x

\int 6 x d x = 3 x^{2}

\int 24 d x = 24 x

= - 3 x^{2} + 24 x

Add a constant to the solution

= - 3 x^{2} + 24 x + C

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