What is the integral of csc(1-2x)cot(1-2x) ?

The integral of csc(1-2x)cot(1-2x) is 1/2 csc(1-2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of csc(1-2x)cot(1-2x)

\int csc (1 - 2 x) cot (1 - 2 x) d x

\frac{1}{2} csc (1 - 2 x) + C

Solution steps

\int csc (1 - 2 x) cot (1 - 2 x) d x

Apply u-substitution

: \int - \frac{1}{2} csc (u) cot (u) d u

= \int - \frac{1}{2} csc (u) cot (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int csc (u) cot (u) d u

Apply u-substitution

: \int - 1 d v

= - \frac{1}{2} \cdot \int - 1 d v

Integral of a constant:

\int a d x = a x

= - \frac{1}{2} (- 1) v

Substitute back

= - \frac{1}{2} (- 1) csc (1 - 2 x)

Simplify

= \frac{1}{2} csc (1 - 2 x)

Add a constant to the solution

= \frac{1}{2} csc (1 - 2 x) + C

\int \frac{b x + c}{x ^{2} - 8 x + 25} d x

\int \frac{15}{( 0.5 t + 1 ) ^{2}} d t

\int 5 x x - 1 d x

\int (\frac{4}{x ^{2} + 1}) d x

\int cos (x) (sin (x) + 1)^{2} d x

What is the integral of csc(1-2x)cot(1-2x) ?
The integral of csc(1-2x)cot(1-2x) is 1/2 csc(1-2x)+C