What is the integral of arcsec(m)x ?

The integral of arcsec(m)x is 1/2 x^2arcsec(m)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of arcsec(m)x

\int arcsec (m) x d x

\frac{1}{2} x^{2} arcsec (m) + C

Solution steps

\int arcsec (m) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= arcsec (m) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= arcsec (m) \frac{x ^{2}}{2}

Simplify

arcsec (m) \frac{x ^{2}}{2} : \frac{1}{2} x^{2} arcsec (m)

= \frac{1}{2} x^{2} arcsec (m)

Add a constant to the solution

= \frac{1}{2} x^{2} arcsec (m) + C

\int (1 + sec (π x))^{2} sec (π x) tan (π x) d x

\int (\frac{5}{1 - x ^{2}}) d x

\int ∣ x - 6 ∣ d x

\int \frac{4 t ^{4} + 48 t ^{9}}{t ^{5} + 6 t ^{10}} d t

\int (4 x^{4} - 2 x^{2} + x - 5) (4 x^{3} - x + \frac{1}{4}) d x

What is the integral of arcsec(m)x ?
The integral of arcsec(m)x is 1/2 x^2arcsec(m)+C