What is the integral of-1.09+5.8e^{-0.25x} ?

The integral of-1.09+5.8e^{-0.25x} is -1.09x-23.2e^{-0.25x}+C

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integral of-1.09+5.8e^{-0.25x}

\int - 1.09 + 5.8 e^{- 0.25 x} d x

- 1.09 x - 23.2 e^{- 0.25 x} + C

Solution steps

\int - 1.09 + 5.8 e^{- 0.25 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1.09 d x + \int 5.8 e^{- 0.25 x} d x

\int 1.09 d x = 1.09 x

\int 5.8 e^{- 0.25 x} d x = - 23.2 e^{- 0.25 x}

= - 1.09 x - 23.2 e^{- 0.25 x}

Add a constant to the solution

= - 1.09 x - 23.2 e^{- 0.25 x} + C

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What is the integral of-1.09+5.8e^{-0.25x} ?
The integral of-1.09+5.8e^{-0.25x} is -1.09x-23.2e^{-0.25x}+C