What is the integral of (-2)/(x^2+1) ?

The integral of (-2)/(x^2+1) is -2arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-2)/(x^2+1)

\int \frac{- 2}{x ^{2} + 1} d x

- 2 arctan (x) + C

Solution steps

\int \frac{- 2}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= - 2 arctan (x)

Add a constant to the solution

= - 2 arctan (x) + C

\int 2 x + 0 d x

\int sin (ln (x)) d x

\int (x e^{x y}) d y

\int 0.5 + \frac{0.2}{x} d x

\int (7 x^{8} + \frac{2}{3} x^{4} - x + 4) d x

What is the integral of (-2)/(x^2+1) ?
The integral of (-2)/(x^2+1) is -2arctan(x)+C