What is the integral of 1/9 cos(θ) ?

The integral of 1/9 cos(θ) is 1/9 sin(θ)+C

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integral of 1/9 cos(θ)

\int \frac{1}{9} cos (θ) d θ

\frac{1}{9} sin (θ) + C

Solution steps

\int \frac{1}{9} cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= \frac{1}{9} sin (θ)

Add a constant to the solution

= \frac{1}{9} sin (θ) + C

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