What is the integral of 3x^2-6sqrt(x) ?

The integral of 3x^2-6sqrt(x) is x^3-4x^{3/2}+C

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integral of 3x^2-6sqrt(x)

\int 3 x^{2} - 6 x d x

x^{3} - 4 x^{\frac{3}{2}} + C

Solution steps

\int 3 x^{2} - 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 6 x d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 4 x^{\frac{3}{2}}

= x^{3} - 4 x^{\frac{3}{2}}

Add a constant to the solution

= x^{3} - 4 x^{\frac{3}{2}} + C

\int 20 cos (x) e^{- 2 x} d x

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\int \frac{1}{a ^{2}} d a

\int x^{- 3} + 7 x^{- 1} d x

What is the integral of 3x^2-6sqrt(x) ?
The integral of 3x^2-6sqrt(x) is x^3-4x^{3/2}+C