What is the integral of (sin(3x)cos(x)) ?

The integral of (sin(3x)cos(x)) is 1/2 (-1/4 cos(4x)-1/2 cos(2x))+C

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integral of (sin(3x)cos(x))

\int (sin (3 x) cos (x)) d x

\frac{1}{2} (- \frac{1}{4} cos (4 x) - \frac{1}{2} cos (2 x)) + C

Solution steps

\int sin (3 x) cos (x) d x

Use the following identity:

cos (t) sin (s) = \frac{sin ( s + t ) + sin ( s - t )}{2}

= \int \frac{sin ( 3 x + x ) + sin ( 3 x - x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (3 x + x) + sin (3 x - x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int sin (3 x + x) d x + \int sin (3 x - x) d x)

\int sin (3 x + x) d x = - \frac{1}{4} cos (4 x)

\int sin (3 x - x) d x = - \frac{1}{2} cos (2 x)

= \frac{1}{2} (- \frac{1}{4} cos (4 x) - \frac{1}{2} cos (2 x))

Add a constant to the solution

= \frac{1}{2} (- \frac{1}{4} cos (4 x) - \frac{1}{2} cos (2 x)) + C

\int 2 1 + x^{3} d x

\int \frac{1}{2 ( 1 - x )} d x

\int a^{x^{2}} d x

\int (3 cos (x) - \frac{1}{x}) d x

What is the integral of (sin(3x)cos(x)) ?
The integral of (sin(3x)cos(x)) is 1/2 (-1/4 cos(4x)-1/2 cos(2x))+C