What is the integral of 3x\sqrt[3]{x} ?

The integral of 3x\sqrt[3]{x} is 3(1/2 x^2\sqrt[3]{x}-1/14 x^{7/3})+C

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integral of 3x\sqrt[3]{x}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

\int \frac{1}{6} x^{\frac{4}{3}} d x = \frac{1}{14} x^{\frac{7}{3}}

Add a constant to the solution

\int x^{4} sec (x^{5}) tan (x^{5}) d x

\int \frac{x}{( x ^{2} + 1 ) ( x - 2 )} d x

\int 2 ln (y) d y

\frac{1}{( 1 + x ^{2} ) ^{2}}

\int \frac{1}{( x ^{2} + x + 1 ) ( x ^{2} + 1 )} d x

What is the integral of 3x\sqrt[3]{x} ?
The integral of 3x\sqrt[3]{x} is 3(1/2 x^2\sqrt[3]{x}-1/14 x^{7/3})+C