What is the integral of x/((x^2+1)(x-2)) ?

The integral of x/((x^2+1)(x-2)) is 1/5 (-ln|x^2+1|+arctan(x))+2/5 ln|x-2|+C

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integral of x/((x^2+1)(x-2))

\int \frac{x}{( x ^{2} + 1 ) ( x - 2 )} d x

\frac{1}{5} (- ln x^{2} + 1 + arctan (x)) + \frac{2}{5} ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x}{( x ^{2} + 1 ) ( x - 2 )} d x

Take the partial fraction of

\frac{x}{( x ^{2} + 1 ) ( x - 2 )} : \frac{- 2 x + 1}{5 ( x ^{2} + 1 )} + \frac{2}{5 ( x - 2 )}

= \int \frac{- 2 x + 1}{5 ( x ^{2} + 1 )} + \frac{2}{5 ( x - 2 )} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{- 2 x + 1}{5 ( x ^{2} + 1 )} d x + \int \frac{2}{5 ( x - 2 )} d x

\int \frac{- 2 x + 1}{5 ( x ^{2} + 1 )} d x = \frac{1}{5} (- ln x^{2} + 1 + arctan (x))

\int \frac{2}{5 ( x - 2 )} d x = \frac{2}{5} ln ∣ x - 2 ∣

= \frac{1}{5} (- ln x^{2} + 1 + arctan (x)) + \frac{2}{5} ln ∣ x - 2 ∣

Add a constant to the solution

= \frac{1}{5} (- ln x^{2} + 1 + arctan (x)) + \frac{2}{5} ln ∣ x - 2 ∣ + C

\int 2 ln (y) d y

\frac{1}{( 1 + x ^{2} ) ^{2}}

\int \frac{1}{( x ^{2} + x + 1 ) ( x ^{2} + 1 )} d x

\int (3 x^{2} - 4 x - 5) d x

\int \frac{2 x}{6 x - x ^{2}} d x

What is the integral of x/((x^2+1)(x-2)) ?
The integral of x/((x^2+1)(x-2)) is 1/5 (-ln|x^2+1|+arctan(x))+2/5 ln|x-2|+C