What is the integral of 2ln(y) ?

The integral of 2ln(y) is 2(yln(y)-y)+C

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integral of 2ln(y)

\int 2 ln (y) d y

2 (y ln (y) - y) + C

Solution steps

\int 2 ln (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int ln (y) d y

Apply Integration By Parts

: y ln (y) - \int 1 d y

= 2 (y ln (y) - \int 1 d y)

\int 1 d y = y

= 2 (y ln (y) - y)

Add a constant to the solution

= 2 (y ln (y) - y) + C

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