What is the integral of 6xsin(3x^2) ?

The integral of 6xsin(3x^2) is -cos(3x^2)+C

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integral of 6xsin(3x^2)

\int 6 x sin (3 x^{2}) d x

- cos (3 x^{2}) + C

Solution steps

\int 6 x sin (3 x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x sin (3 x^{2}) d x

Apply u-substitution

: \int \frac{sin ( u )}{6} d u

= 6 \cdot \int \frac{sin ( u )}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{6} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 6 \cdot \frac{1}{6} (- cos (u))

Substitute back

u = 3 x^{2}

= 6 \cdot \frac{1}{6} (- cos (3 x^{2}))

Simplify

6 \cdot \frac{1}{6} (- cos (3 x^{2})) : - cos (3 x^{2})

= - cos (3 x^{2})

Add a constant to the solution

= - cos (3 x^{2}) + C

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What is the integral of 6xsin(3x^2) ?
The integral of 6xsin(3x^2) is -cos(3x^2)+C