What is the integral of 9cot(x)sin(x) ?

The integral of 9cot(x)sin(x) is 9sin(x)+C

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integral of 9cot(x)sin(x)

\int 9 cot (x) sin (x) d x

9 sin (x) + C

Solution steps

\int 9 cot (x) sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cot (x) sin (x) d x

Express with sin, cos

= 9 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 9 sin (x)

Add a constant to the solution

= 9 sin (x) + C

\int (x 3 x) d x

\int \frac{a ^{2} x ^{2}}{x ^{3} + a} d x

\int (x + 1)^{2} - 1 d x

\int \frac{1}{x ( 2 x - 1 )} d x

\int \frac{x}{x ^{4} + 4} d x

What is the integral of 9cot(x)sin(x) ?
The integral of 9cot(x)sin(x) is 9sin(x)+C